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8 January, 09:45

If 600.0 ml of air at 20.0 c is heated to 60.0L, what will be its volume

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  1. 8 January, 12:03
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    P1v1/t1 = p2t2/t2

    p is constant

    v1=600, t1 = 20c=293K

    v2=?, t2=60c=333K

    temperature must be in Kelvin

    do the math
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