Determine the osmotic pressure of a solution that contains 0.048 g of a hydrocarbon solute (molar mass = 340 g/mol0

M (CH) = 0.048 g

M (CH) = 340 g/mol

V = 350 mL = 0.35 L

T = 20 C = 293 K

π = ?

For determination of osmotic pressure we will use next equation:

π = c x R x T

c = n/V

n = m/M = 0.048/340 = 0.00014 mol

c = 0.00014/0.35 = 0.0004 mol/L

π = 0.0004 mol/L * 8.314 LkPa/Kmol * 293 K

π = 0.97 kPa