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10 June, 13:29

Determine the osmotic pressure of a solution that contains 0.048 g of a hydrocarbon solute (molar mass = 340 g/mol0

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  1. 10 June, 14:46
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    M (CH) = 0.048 g

    M (CH) = 340 g/mol

    V = 350 mL = 0.35 L

    T = 20 C = 293 K

    π = ?

    For determination of osmotic pressure we will use next equation:

    π = c x R x T

    c = n/V

    n = m/M = 0.048/340 = 0.00014 mol

    c = 0.00014/0.35 = 0.0004 mol/L

    π = 0.0004 mol/L * 8.314 LkPa/Kmol * 293 K

    π = 0.97 kPa
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