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14 March, 15:18

Calculate how much 95% ethyl alcohol will be required to dissolve 0.1 g of sulfanilamide at 78 c using volume calculate how much sulfanilamide will remain dissolved after mixture is cooled to 0

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  1. 14 March, 16:49
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    According to the source below, the solubility of sulfanilamide in 95% ethyl alcohol at 78°C is 210 mg/mL. Since 0.1 g = 100 mg, we can set up a proportion:

    (210 mg) / (1 mL) = (100 mg) / (x mL) Solving, x = 0.48 mL of 95% ethyl alcohol will be required.

    I do not know previously the solubility of sulfanilamide in 95% ethyl alcohol. Let us accept the solubility you quoted here.

    100/210 = 0.47619047619 ... ≈ 0.48 (ml)

    at 0C, the amount of sulfanilamide remains in the solution is: 14 * (100/210) = 6.67 (mg), since you only have 0.48 ml solution.

    The volume of the solution will change a little by cooling from 78C to 0C. You may also consider this volume change if you have data.
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