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26 March, 14:47

What is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid?

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  1. 26 March, 17:50
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    So in this problem, your limiting reactant is the 5.00 mol of Zn, because you have an excess of hydrochloric acid.

    The first step to answering this problem is to set up a balanced equation.

    You start with Zn + HCl ⇒ ZnCl + H

    In order to balance it, you have to know that Zinc is a + 2 ion, Cl is a - 1 ion, and H is a + 1 ion. Each molecule must be balanced (meaning ionic charges equal to zero), as well as the number of each element on either side of the reaction.

    This gives you Zn + 2HCl ⇒ ZnCl₂ + 2H

    Now, in order to find how much Hydrogen gas you have, you have to know how many atoms of Zn you have.

    1 mol is 6.022 * 10²⁴ atoms (Avogadro's Number), so if you have 5 mol of Zn, you have 3.011 * 10²⁵ atoms of zinc.

    Plug this into the reaction and re-balance the formula.

    (3.011 * 10²⁵ Zn) + (6.022 * 10²⁵ HCl) ⇒ (3.011 * 10²⁵ ZnCl₂) +

    (6.022 * 10²⁵ H)

    You end up with (6.022 * 10²⁵ H), or 10.00 mol H (g)
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