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5 April, 13:57

How many grams nano3 add to 500g of h20 prepare solution. 5 molal nano3?

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  1. 5 April, 15:14
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    Answer is: mass of sodium nitrate is 21,25 g.

    m (H₂O) = 500 g · 1 kg/1000 g = 0,5 kg.

    b (solution) = 0,500 m = 0,500 mol/kg.

    m (NaNO₃) = ?

    b (solution) = n (NaNO₃) : m (H₂O).

    n (NaNO₃) = 0,500 mol/kg · 0,5 kg.

    n (NaNO₃) = 0,25 mol.

    m (NaNO₃) = n (NaNO₃) · M (NaNO₃).

    m (NaNO₃) = 0,25 mol · 85 g/mol.

    m (NaNO₃) = 21,25 g.
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