Given the information for reaction 1 at a specific temperature; calculate kc for reaction 2 at the same temperature. reaction 1: 2ch4 (g) ⇄ c2h2 (g) + 3h2 (g) kc = 0.020 reaction 2: 2c2h2 (g) + 6h2 (g) ⇄ 4ch4 (g)

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Chemistry

Harmony Burke

18 July, 22:13

Given the information for reaction 1 at a specific temperature; calculate kc for reaction 2 at the same temperature. reaction 1: 2ch4 (g) ⇄ c2h2 (g) + 3h2 (g) kc = 0.020 reaction 2: 2c2h2 (g) + 6h2 (g) ⇄ 4ch4 (g)

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Imani Deleon · Answer 1

Answer is: equilibrium constants is 2500.

Chemical reaction 1: 2CH₄ (g) ⇄ C₂H₂ (g) + 3H₂ (g); Kc₁ = 0,020.

Chemical reaction 2: 2C₂H₂ (g) + 6H₂ (g) ⇄ 4CH₄ (g); Kc₂ = ?

Chemical reaction 2 is reverse chemical reaction 1 multiply with two:

Kc₂ = 1 : (Kc₁) ².

Kc₂ = 1 : (0,020) ².

Kc₂ = 1 : 0,0004.

Kc₂ = 2500 = 2,5·10³.