Pure oxygen gas was first prepared by heating mercury (ii) oxide, hgo: 2hgo (s) →2hg (l) + o2 (g) what volume (in l) of oxygen at stp is released by heating 10.36 g of hgo?

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Chemistry

Macie Benitez

13 August, 04:51

Pure oxygen gas was first prepared by heating mercury (ii) oxide, hgo: 2hgo (s) →2hg (l) + o2 (g) what volume (in l) of oxygen at stp is released by heating 10.36 g of hgo?

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Ross Meyer · Answer 1

Answer: Moles HgO = 10.36 g / 216.59 g/mol = 0.048 the ratio between HgO and O2 is 2 : 1 moles O2 formed = 0.048 / 2 = 0.024 at STP one mole of any gas occupies 22.4 L Volume O2 = 0.024 x 22.4 L/mol = 0.54 L