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30 July, 03:22

Find the ph of a 0.155 m hclo2 (aq) solution. for hclo2, ka = 0.011.

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  1. 30 July, 05:39
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    Ka = [H=][ClO2-]/[HClO2] = 0.011

    Let [H+] = x. Then [ClO2-] = x and [HClO2] = 0.155 - x. But x is very small, so we can neglect it and say that [HClO2] = 0.155.

    Ka = (x) (x) / (0.155) = 0.011

    x^2 = 0.01705

    x = 0.1306 [H+]

    pH = - Log[H+], and Log (0.1306) = - 0.8841, so pH = + 0.8841
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