Consider the reaction:

8H2S (g) + 4O2 (g) →8H2O (g) + S8 (g)

Δ[H2S]/Δt = - 0.085 M/s.

Δ[H2O]/Δt

Question

Chemistry

Mariyah Dean

8 September, 12:16

Consider the reaction:

8H2S (g) + 4O2 (g) →8H2O (g) + S8 (g)

Δ[H2S]/Δt = - 0.085 M/s.

Δ[H2O]/Δt

+2

Answers (1)

Know the Answer?

Jefferson Wilcox · Answer 1

Gosh, I love chem!

[H2O]/t should be 0.085M/s

this is because of the coefficients in front of H2S and H2O being the same.

the significance of this answer is that the H2S disappears at the same rate H2O appears.

Consider the reaction:8H2S (g) + 4O2 (g) →8H2O (g) + S8 (g)Δ[H2S]/Δt = - 0.085 M/s.Δ[H2O]/Δt

Consider the reaction:

8H2S (g) + 4O2 (g) →8H2O (g) + S8 (g)

Δ[H2S]/Δt = - 0.085 M/s.

Δ[H2O]/Δt