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2 October, 19:53

ZnO + 2HCl - - > ZnCl2 + H2O

what is the maximum amount of ZnCl2 which could be formed from 3.52 mol of ZnO and 18.82 mol of HCl

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  1. 2 October, 21:14
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    Theoretical yield is the maximum amount of product that could be formed from amounts of reactants.

    Now, in this problem we will find the theoretical yield of ZnCl2

    3.52 mol ZnO x (1 mol ZnCl2 / 1 mol ZnO) = 3.52 mol ZnCl2

    18.82 mol HCl x (1 mol ZnCl2 / 2 mol HCl) = 9.41 mol ZnCl2

    ZnO is the limiting reactant.

    Therefore, we form 3.52 mol of ZnCl2

    molar mass of ZnCl2 is

    1 (65.38) + 2 (35.45) = 135.28 g/mol

    This has a mass of

    m = M x n

    m = 135.28 g/mol ZnCl2 x 3.52 mol ZnCl2

    m = 476.2 g ZnCl2

    Answer: maximum amount of ZnCl2 is 476.2 g
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