At 25.0∘c, the molar solubility of silver chromate in water is 1.10*10-12 m. calculate the solubility in grams per liter. express your answer in grams per liter to three significant figures. how many liters of water are required to dissolve 1.00 g of silver chromate? express your answer in liters to three significant figures.

Question

Chemistry

Kole Cannon

14 June, 16:44

At 25.0∘c, the molar solubility of silver chromate in water is 1.10*10-12 m. calculate the solubility in grams per liter. express your answer in grams per liter to three significant figures. how many liters of water are required to dissolve 1.00 g of silver chromate? express your answer in liters to three significant figures.

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Answers (1)

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Jovany Stokes · Answer 1

The molar mass of Silver Chromate is 331.73 g/mol.

Therefore:

solubility = 1.10*10^-12 mol / L * (331.73 g/mol) = 3.65x10^-10 g/L

The volume required is:

volume = 1 g / (3.65x10^-10 g/L) = 2,740,454,313 L = 2.74x10^9 L