Ask Question
14 June, 16:44

At 25.0∘c, the molar solubility of silver chromate in water is 1.10*10-12 m. calculate the solubility in grams per liter. express your answer in grams per liter to three significant figures. how many liters of water are required to dissolve 1.00 g of silver chromate? express your answer in liters to three significant figures.

+2
Answers (1)
  1. 14 June, 17:00
    0
    The molar mass of Silver Chromate is 331.73 g/mol.

    Therefore:

    solubility = 1.10*10^-12 mol / L * (331.73 g/mol) = 3.65x10^-10 g/L

    The volume required is:

    volume = 1 g / (3.65x10^-10 g/L) = 2,740,454,313 L = 2.74x10^9 L
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “At 25.0∘c, the molar solubility of silver chromate in water is 1.10*10-12 m. calculate the solubility in grams per liter. express your ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers