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11 June, 05:41

What is % w/w of 18 m naoh? density 1.48 g/ml?

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Answers (1)
  1. 11 June, 06:32
    0
    As,

    w/w % = weight of Solute / Weight of Solution * 100 - - - (1)

    Finding weight of Solute:

    As,

    1 mole of NaOH = 40 g

    So,

    18 moles = X g

    Solving for X,

    X = (18 mol * 40 g) : 1 mol

    X = 720 g

    Finding mass of Solution:

    Multiply density of the solution by 100 mL

    So,

    = 1.48 g/mL * 1000 mL

    = 1480 g

    Putting values in eq. 1,

    w/w % = 720 g / 1480 * 100

    w/w % = 48.64 %
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