Ask Question
16 May, 15:33

What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.884 M with a k value of 5.42 * 10-2 M/s?

+4
Answers (1)
  1. 16 May, 17:09
    0
    Answer: 8.15s

    Explanation:

    1) A first order reaction is that whose rate is proportional to the concenration of the reactant:

    r = k [N]

    r = - d[N]/dt =

    => - d[N]/dt = k [N]

    2) When you integrate you get:

    N - No = - kt

    3) Half life = > N = No / 2, t = t'

    => No - No / 2 = kt' = > No / 2 = kt' = > t' = (No/2) / k

    3) Plug in the data given: No = 0.884M, and k = 5.42x10⁻²M/s

    t' = (0.884M/2) / (5.42x10⁻²M/s) = 8.15s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.884 M with a k value of 5.42 * ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers