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22 February, 12:06

A 92.8 gram sample of Ba (OH) 2•4H2O (barium hydroxide tetrahydrate) is heated until water is released. How many grams of water were released?

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  1. 22 February, 12:33
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    From the periodic table:

    molar mass of barium = 137.2 grams

    molar mass of oxygen = 16 grams

    molar mass of hydrogen = 1 gram

    molar mass of Ba (OH) 2 = 137.2 + 2 (16) + 2 (1) = 171.2 grams

    molar mass of 4H2O = 4 [2 (1) + 16] = 72 grams

    molar mass of Ba (OH) 2.4H2O = 171.2 + 72 = 243.2 grams

    Therefore, each 243.2 grams of barium hydroxide tetrahydrate contains 72 grams of water, thus, 92.8 grams will contain:

    mass of water in 92.8 grams = (92.8 x 72) / 243.2 = 27.474 grams

    Based on this, when a 92.8 gram sample of Ba (OH) 2•4H2O (barium hydroxide tetrahydrate) is heated until water is released, 27.474 grams of water will be released.
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