Calculate the theoretical yield if 100.0 g p4o10 react with 200.0 g h2o

The reaction of Phosphorous Pentaoxide with water yield Phosphoric Acid as shown below,

P₄O₁₀ + 6 H₂O → 4 H₃PO₄

According to balance equation,

283.88 g (1 mole) P₄O₁₀ requires = 108 g (6 mole) of H₂O

So,

100 g P₄O₁₀ will require = X g of H₂O

Solving for X,

X = (100 g * 108 g) : 283.88 g

X = 38.04 g of H₂O

So, 100 g P₄O₁₀ requires 38.04 g of H₂O, while we are provided with 200 g of H₂O which means that water is in excess and P₄O₁₀ is limiting reagent. Therefore, P₄O₁₀ will control the yield of H₃PO₄. So,

As,

283.88 g (1 mole) P₄O₁₀ produced = 391.96 g (4 mole) of H₃PO₄

So,

100 g P₄O₁₀ will produce = X g of H₃PO₄

Solving for X,

X = (100 g * 391.96 g) : 283.88 g

X = 138.07 g of H₃PO₄

Result:

Theoretical Yield of this reaction is 138.07 g.