Ask Question
29 April, 01:14

Calculate the ph of the resulting solution if 34.0 ml of 0.340 m hcl (aq is added to

+2
Answers (1)
  1. 29 April, 03:22
    0
    According to the reaction equation:

    HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)

    a) Part 1):

    first, we need to get moles HCl = molarity * volume

    = 0.34m * 0.034

    = 0.01156 mol

    then, we need moles of NaOH = molarity * volume

    = 0.34 * 0.039

    = 0.01326 mol

    when NaOH excess:

    ∴ NaOH remaining = 0.01326 - 0.01156

    = 0.0017 mol

    when the total volume = 0.039 + 0.034

    = 0.073 L

    ∴[OH] = moles / total volume

    = 0.0017mol / 0.073 L

    = 0.0233 M

    ∴ POH = - ㏒[OH-]

    = - ㏒0.0233

    = 1.63

    ∴ PH = 14 - 1.63

    = 12.37

    b) part 2:

    as we got moles HCl = molarity * volume

    = 0.34 * 0.034

    = 0.01156 mol

    then moles NaOH = molarity * volume

    = 0.39 * 0.044

    = 0.01716 mol

    NaOH remaining = 0.01716 - 0.01156

    = 0.0056 mol

    when the total volume = 0.034 + 0.044

    = 0.078 L

    ∴[OH-] = 0.0056 / 0.078

    = 0.0718 M

    ∴ POH = - ㏒[OH-]

    = - ㏒0.0718

    = 1.14

    ∴PH = 14 - POH

    = 14 - POH

    = 14 - 1.14

    = 12.86
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the ph of the resulting solution if 34.0 ml of 0.340 m hcl (aq is added to ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers