How many moles of agcl are contained in 244 ml of 0.135 m agcl solution. the density of the solution is 1.22 g/ml?

Question

Chemistry

Ashton

19 May, 10:57

How many moles of agcl are contained in 244 ml of 0.135 m agcl solution. the density of the solution is 1.22 g/ml?

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Conor Kaiser · Answer 1

Answer is: 3,94·10⁻² moles of silver chloride are contained in 244 ml of solution.

V (AgCl) = 244 ml = 0,244 l.

b (AgCl) = 0,135 mol/kg.

d (AgCl) = 1,22 g/ml.

m (AgCl) = V (AgCl) · d (AgCl).

m (AgCl) = 244 ml · 1,22 g/ml.

m (solution AgCl) = 297,68 g.

m (AgCl) = 0,135 mol ·143,3 g/mol = 19,34 g.

ω = 19,34 g : 19,34 g + 1000 g = 0,0189.

m (AgCl) = 0,0189 · 297,68 g = 5,64 g.

n (AgCl) = 5,64 g : 143,3 g/mol = 0,0394 mol.