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26 July, 14:36

How many moles of air must escape from a 10-m  8.0-m  5.0-m room when the temperature is raised from 0c to 20c? assume the pressure remains unchanged at one atmosphere while the room is heated?

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  1. 26 July, 16:25
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    dа ta:

    p = 1 atm

    V = 10 m * 8 m * 5 m = 400 m^3 = 400,000 liter

    To = 0 + 273.15K = 273.15K

    Tf = 20 + 273.15K = 293.15K

    No - Nf = ?

    2) Formula

    pV = NRT = > N = pV / (RT)

    3) solution

    No = pV / (RTo)

    Nf = pV / (RTf)

    => No - Nf = [pv / R] [ 1 / To - 1 / Tf ]

    => No - Nf = [1atm*400,000liter / 0.0821 atm*liter/K*mol ] [ 1 / 273.15 - 1 / 293.15]

    No - Nf = 1216.9 moles ≈ 1217 moles

    Answer: 1217 moles
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