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26 March, 15:56

I WIll upvote for answer

Balance the following reaction Fe^2 O ^3 + HCI+FeCI^3+H^2O

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  1. 26 March, 19:20
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    Let's balance step by step. We'll start with Iron (Fe)

    Fe2O3 + HCl - - > FeCl3 + H2O

    We have 2 Fe on the left, and only one on the right, so we'll double the Fe on the right

    Fe2O3 + HCl - - > 2FeCl3 + H2O

    Now we have six Cl on the right, and only one on the left, so we'll multiply the Cl by six on the left

    Fe2O3 + 6HCl - - > 2FeCl3 + H2O

    Finally, we can balance the water, as we have 6 H and 3 O on the left, and 2 H and one O on the right, so we can triple the H2O on the right

    Fe2O3 + 6HCl - - > 2FeCl3 + 3H2O

    The equation has been balanced.
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