What volume of a 0.160 m solution of koh must be added to 450.0 ml of the acidic solution to completely neutralize all of the acid?

An acidic solution is 0.1M in HCl and 0.2 H2so4. volume is equal to no of moles divided by molarity.

number of moles of HCl is 450ml x 0.1 divided by 1000 which is equal to 0.045 moles

volume of HCl is therefore 0.45 divided by 0.16 which is 2.81 litres

Number of moles of H2so4 is 450ml x 0.2 divided by 1000 which is equal to 0.09 moles

volume of H2SO4 IS 0.09 divided by 0.16 which is equal to 0.56 litres