How many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution

The moles of potassium that you would need to prepare 1200 g of 5% potassium sulfate solution is 1.538 moles

calculation

calculate the mass potassium using the below formula

%M/M = mass of the solute (potassium) / mass of the solvent (potassium sulfate solution)

let the mass of potassium be represented by Y

then convert % into fraction = 5/100

5/100 = Y/1200

cross multiplication

100y = 6000

divide both side by 100

Y = 60 g

moles of potassium = mass/molar mass

= 60/39=1.538