Calculate the volume of 2.0116 x 10^23 molecules of nh3 gas trapped in a container at a pressure of 2280.0 mmhg and a temperature of 41.000 c

The problem in this question can be solved using the ideal gas formula. Ideal gas formula show interaction between the pressure, volume, temperature and the number of molecules.

n = number of molecule / avogadro number

n = (2.0116 x 10^23 / 6.02*10^23) = 1/3 mole

T = celcius + 273.15

T = (41+273.15) K=314.15

P=2280 mmHg / (760mmHg/atm) = 3 atm

PV=nRT

V = nrT / P

V = 1/3 moles * (0.08205 L atm / mol·K) * 314.15 K / 3 atm

V = 2.864 L