Ask Question
5 October, 03:43

The atmosphere contained approximately 115 ppmv of anthropogenic co2 (g) in 2010. if 1 ppmv - co2 (g) is equivalent to 2184.82 tg-c (teragrams, or 1012 g, of atomic carbon), calculate how many metric tonnes of quicklime [cao (s) ] were needed to fix

+1
Answers (1)
  1. 5 October, 04:37
    0
    Answer is: 3,2 · 10¹¹ t of quicklime.

    Chemical reaction: CO₂ + CaO → CaCO₃.

    m (CO₂) = 2184,82·10¹² · 115 = 2,51 · 10¹⁷ g.

    n (CO₂) = m (CO₂) : M (CO₂)

    n (CO₂) = 2,51 · 10¹⁷ g : 44 g/mol = 5,7 · 10¹⁵ mol.

    from reaction n (CO₂) : n (CaO) = 1 : 1.

    n (CaO) = 5,7· 10¹⁵ mol.

    m (CaO) = 5,7· 10¹⁵ mol · 56 g/mol = 3,2 · 10¹⁷ g = 3,2 · 10¹¹ t.

    n - amount of substance.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The atmosphere contained approximately 115 ppmv of anthropogenic co2 (g) in 2010. if 1 ppmv - co2 (g) is equivalent to 2184.82 tg-c ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers