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23 June, 17:15
How to calculate the pH of NH4OH (0.1M)
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Rashad Mason
23 June, 17:26
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Answer is: pH of ammonium hydroxide is 11.13.
Chemical reaction of ammonium hydroxide in water: NH₄OH → NH₄⁺ + OH⁻.
Kb (NH₄OH) = 1,8·10⁻⁵.
c ₀ (NH₄OH) = 0.1 M.
c (NH ₄⁺) = c (OH⁻) = x.
c (NH₄OH) = 0.1 M - x.
Kb = c (NH ₄⁺) · c (OH⁻) / c (NH₄OH).
0,000018 = x² / 0.1 mol/L - x.
Solve quadratic equation: x = c (OH⁻) = 0.00133 M.
pOH = - logc (OH⁻).
pOH = 2.87.
pH = 14 - 2.87.
pH = 11.13.
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