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23 June, 17:15

How to calculate the pH of NH4OH (0.1M)

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  1. 23 June, 17:26
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    Answer is: pH of ammonium hydroxide is 11.13.

    Chemical reaction of ammonium hydroxide in water: NH₄OH → NH₄⁺ + OH⁻.

    Kb (NH₄OH) = 1,8·10⁻⁵.

    c ₀ (NH₄OH) = 0.1 M.

    c (NH ₄⁺) = c (OH⁻) = x.

    c (NH₄OH) = 0.1 M - x.

    Kb = c (NH ₄⁺) · c (OH⁻) / c (NH₄OH).

    0,000018 = x² / 0.1 mol/L - x.

    Solve quadratic equation: x = c (OH⁻) = 0.00133 M.

    pOH = - logc (OH⁻).

    pOH = 2.87.

    pH = 14 - 2.87.

    pH = 11.13.
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