What is the volume occupied by 3.00 * 1023 molecules of bromine gas at STP?

a 404.5 L

B. 0.80 L

C. 2.2 * 10-2

D. 11.2 L

Question

Chemistry

Kaylah Garner

26 October, 03:37

What is the volume occupied by 3.00 * 1023 molecules of bromine gas at STP?

a 404.5 L

B. 0.80 L

C. 2.2 * 10-2

D. 11.2 L

+5

Answers (1)

Know the Answer?

Lillie Mays · Answer 1

D. 11.2 L, since we are at STP we will use the ideal gas law. 3.0 x 10²³ 6.02x10²³ / 1 mole and if you continue with this process it will give you 11 L.

What is the volume occupied by 3.00 * 1023 molecules of bromine gas at STP?a 404.5 LB. 0.80 LC. 2.2 * 10-2D. 11.2 L

What is the volume occupied by 3.00 * 1023 molecules of bromine gas at STP?

a 404.5 L

B. 0.80 L

C. 2.2 * 10-2

D. 11.2 L