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18 August, 07:38

In a sample consisting of 1.00 mol nabr and 0.300 mol ki, what is the mass percent of iodine? (a) 24.9% (b) 32.6% (c) 47.2% (d) 83.1

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  1. 18 August, 10:43
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    The quantities you have to know are the molar masses and the molecular stoichiometric ratios. The solution for this problem is as follows:

    Mass Percent of Iodine = (Mass of Iodine/Mass of NaBr and KI) * 100

    Mass of NaBr = 1 mol NaBr * 102.89 g/mol = 102.89 g

    Mass of KI = 0.3 mol KI * 166 g/mol = 49.8 g

    Mass of KI = 0.3 mol KI * 1 mol I/1mol KI * 1 mol I₂/2 mol I * 253.81 g/mol = 38.07 g

    Mass %I₂ = 38.07 / (102.89+49.8) * 100 = 24.9%
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