Using the following thermochemical data, what is the change in enthalpy for the following reaction?

Ca (OH) 2 (aq) + 2HCl (aq) → CaCl2 (aq) + 2H2O (l)

CaO (s) + 2HCl (aq) →CaCl2 (aq) + H2O (l), ΔH = - 186kJ

CaO (s) + H2O (l) →Ca (OH) 2 (aq), ΔH = - 65.1 kJ

In calculating the change in enthalpy in a certain reaction, it is important to remember that it is the sum of the enthapy of formation for the substances involved in the reaction.

CaO (s) + 2HCl (aq) →CaCl2 (aq) + H2O (l) ΔH = - 186kJ

Ca (OH) 2 (aq) → CaO (s) + H2O (l) ΔH = 65.1 kJ

Ca (OH) 2 (aq) + 2HCl (aq) → CaCl2 (aq) + 2H2O (l) ΔH = - 120.9 kJ