Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn cat.", then output is:

Censored

Ex: If userInput is "Dang, that was scary!", then output is:

Dang, that was scary!

Note: If the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.

#include

#include

using namespace std;

int main () {

string userInput;

getline (cin, userInput);

int isPresent = userInput. find ("darn");

if (isPresent > 0) {

cout << "Censored" << endl; / * Your solution goes here * /

return 0;

}

Question

Computers & Technology

Camilla Medina

12 October, 06:40

Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn cat.", then output is:

Censored

Ex: If userInput is "Dang, that was scary!", then output is:

Dang, that was scary!

Note: If the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.

#include

#include

using namespace std;

int main () {

string userInput;

getline (cin, userInput);

int isPresent = userInput. find ("darn");

if (isPresent > 0) {

cout << "Censored" << endl; / * Your solution goes here * /

return 0;

}

+2

Answers (1)

Know the Answer?

Norah · Answer 1

The Java code is given below

Explanation:

import java. util.*;

public class CensoredWords {

public static void main (String args[]) {

Scanner scnr=new Scanner (System. in);

String userInput;

System. out. println ("Enter String: ");

userInput=scnr. nextLine ();

int res=userInput. indexOf ("darn");

if (res = = - 1) {

System. out. println (userInput);

} else {

System. out. println ("Censored");

}

}

}