6.31 LAB: Leap year - functions A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is:

Question

Computers & Technology

Patricia Villarreal

19 March, 09:05

6.31 LAB: Leap year - functions A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is:

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Answers (1)

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Felix · Answer 1

The code is given below in C with appropriate comments

Explanation:

#include

#include

bool ISLeapYear (int userYear)

{

/ / If a year is multiple of 400,

/ / then it is a leap year

if (userYear % 400 = = 0)

return true;

/ / Else If a year is multiple of 100,

/ / then it is not a leap year

if (userYear % 100 = = 0)

return false;

/ / Else If a year is multiple of 4,

/ / then it is a leap year

if (userYear % 4 = = 0)

return true;

return false;

}

int main (void) {

int year;

printf ("Enter year : ");

scanf ("%d",&year);

if (ISLeapYear (year)) {

printf ("%d is a leap year.", year);

}else{

printf ("%d is not a leap year.", year);

}

return 0;