What is the output of the following C+ + code? int x = 55; int y = 5; switch (x % 7) { case 0: case 1: y++; case 2: case 3: y = y + 2; case 4: break; c

Complete Question:

What is the output of the following C+ + code?

int x = 55;

int y = 5;

switch (x % 7)

{

case 0:

case 1:

y++;

case 2:

case 3:

y = y + 2;

case 4:

break;

case 5:

case 6:

y = y - 3;

}

cout << y << endl;

A. 2

B. 5

C. 8

D. 10

Answer:

A) 2

Explanation:

In this code snippet provided which shows the use of the switch statement in C++. Two variables have been declared and initialized.

int x=55 and int y = 5;

The condition of the switch statement (x%7) evaluates to 6. Therefore case 6: gets executed which is y-3 and this is equal to 2 since the initial value of y was 5. The output statement cout << y << endl; prints 2 to the console