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28 March, 16:46

Consider the following code: public static void mystery (int a) { System. out. println ("A"); } public static void mystery (double a) { System. out. println ("B"); } public static void mystery (int a, double b) { System. out. println ("C"); } public static void mystery (double a, int b) { System. out. println ("D"); } What is output by the following? mystery (7);

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  1. 28 March, 19:44
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    The output is "A"

    Explanation:

    public class Solution {

    public static void main (String args[]) {

    mystery (7);

    }

    public static void mystery (int a) { System. out. println ("A"); }

    public static void mystery (double a) { System. out. println ("B"); }

    public static void mystery (int a, double b) { System. out. println ("C"); }

    public static void mystery (double a, int b) { System. out. println ("D"); }

    }

    In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.

    In the first case; mystery will be called if the argument is int.

    In the second case; mystery will be called if the argument is double.

    In the third case; mystery will be called if the arguments are int and double.

    In the fourth case; mystery will be called if the arguments are double and int.

    When mystery (7) is called; the mystery method requiring only int will be called and the output is "A".
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