Which line in the following program contains the prototype showDub function? 1 #include 2 using namespace std; 3 void showDub (int); 4 int main () 5 { 6 int x = 2; 7 showDub (x); 8 cout << x << endl; 9 return 0; 10 } 11 void showDub (int num) 12 { 13 cout << (num * 2) << endl; 14 }

Question

Computers & Technology

Kendall Randolph

23 September, 13:36

Which line in the following program contains the prototype showDub function? 1 #include 2 using namespace std; 3 void showDub (int); 4 int main () 5 { 6 int x = 2; 7 showDub (x); 8 cout << x << endl; 9 return 0; 10 } 11 void showDub (int num) 12 { 13 cout << (num * 2) << endl; 14 }

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Answers (1)

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Jaqueline Bailey · Answer 1

Option 3 is the correct answer for the above question.

Explanation:

If any function is defined after the main function or any other function which is used to call that function then there needs a prototype defined before the calling function definition to tell the compiler that what type of that function is. for example, if a fun function is called by the main function and its definition is after the main function, then there needs to declare a function prototype before the main function definition.

The prototype syntax is "return_type function_name (argumen_type1, argument_type2) ". This syntax is matched from option 3. Hence 3 is the correct answer for the above question while the other is not because:-

Option 1 states about the header file. Option 2 states about the namespace name. Option 4 states the main function. Option 5 states about the curly braces. Option 6, 7 and 8 states about the main function statement. Option 9 states the return statement. Option 10 states about the curly braces. Option 11, 12, 13 and 14 states about the definition of showdub function.