Create a cell array containing the same data as above (Do not use built-in functions such as cell2array, struct2cell, etc. but use direct definition). The first row of the array will contain Mercury, 35.98, 3031 etc.

clc;

clear all;

disp ('Creating the cell arr of required values')

arr = { 'Alejandro', 11, {3 5 7 9}, {0 0}, 'UCSD2016'; ...

{8 6 4 2 0 - 2}, pi, 'Stephanie', {1 0}, {' (858) 273-0173'} }

disp ('First row second column')

exp1 = arr (1 : 2, 2)

disp ('Third element of 2nd row 1st column')

exp2 = arr{2, 1} (1,3)

disp ('Deleting last 2 elements of 1st row 2nd column')

arr{1, 3} (3:4) = []

disp ('log of 2nd row 2nd column')

arr{2, 2} = log (arr{2, 2})

disp ('Swapping 1st row 1st column with 2nd row 3rd column')

temp = arr{2, 3};

arr{2, 3} = arr{1, 1}

arr{1, 1} = temp

disp ('Deleting 2nd row 1st column elements')

arr{2, 1} (1:6) = []

disp ('Deleting third column')

arr (:,3) = []