Consider the following pseudocode. How much time does the code take to execute? Express all answers in terms of the input variable n, using Big-Oh O () notation. void george (int n) {int m = n; while (m > 1) { for (int i = 1; i < m; i++) int S = 1; m = m/2; }}

Question

Computers & Technology

Jacob

15 March, 11:01

Consider the following pseudocode. How much time does the code take to execute? Express all answers in terms of the input variable n, using Big-Oh O () notation. void george (int n) {int m = n; while (m > 1) { for (int i = 1; i < m; i++) int S = 1; m = m/2; }}

+2

Answers (1)

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Derrick Galvan · Answer 1

Time the code takes to execute is O (n²)

Explanation:

The code forms an arithmetic series using it two loops.

n + (n-1) + (n-2) + ... + 2+1

=n (n+1) / 2

=O (n²)