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10 July, 22:35

Write a function that is named times_ten and accepts a number as an argument. When the function is called, it should return the value of its argument multiplied by 10.

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  1. 11 July, 00:19
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    It changes a little depending on what programming language you're using, but in C you could say

    int times_ten (int num) {

    num = num*10;

    return num;

    }

    Or, in general terms:

    Integer Function times_ten (Integer num)

    Set num = num * 10

    Return num

    This is all done assuming the number used as an argument is an integer and that you are returning an integer value, not a decimal. The main thing to notice is that since you have to return a value, you must have two things: a return statement, and a type declaration for the function, otherwise you'll get an error.
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