1. Implement the function dict_intersect, which takes two dictionaries as parameters d1 and d2, and returns a new dictionary which contains only those keys which appear in both d1 and d2, whose values are a tuple of the corresponding values from d1 and d2.

E. g., dict_intersect ({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'}) should return {'b': ('banana', 'bee') }

2. Implement the function consolidate, which accepts zero or more sequences in the star parameter seqs, and returns a dictionary whose keys consist of values found in those sequences, which in turn map to numbers indicating how many times each value appears across all the sequences.

E. g., consolidate ([1,2,3], [1,1,1], [2,4], [1]) should return the dictionary {1: 5, 2: 2, 3: 1, 4: 1}.

Question

Computers & Technology

Glass

21 July, 19:20

1. Implement the function dict_intersect, which takes two dictionaries as parameters d1 and d2, and returns a new dictionary which contains only those keys which appear in both d1 and d2, whose values are a tuple of the corresponding values from d1 and d2.

E. g., dict_intersect ({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'}) should return {'b': ('banana', 'bee') }

2. Implement the function consolidate, which accepts zero or more sequences in the star parameter seqs, and returns a dictionary whose keys consist of values found in those sequences, which in turn map to numbers indicating how many times each value appears across all the sequences.

E. g., consolidate ([1,2,3], [1,1,1], [2,4], [1]) should return the dictionary {1: 5, 2: 2, 3: 1, 4: 1}.

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Answers (1)

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Gilbert Forbes · Answer 1

1

def dict_intersect (d1, d2) : #create dictionary

d3={} #dictionaries

for key1, value1 in d1. items () : #iterate through the loop

if key1 in d2: #checking condition

d3[key1] = (d1[key1], d2[key1]) #add the items into the dictionary

return d 3

print (dict_intersect ({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'})) #display

2

def consolidate (*l1) : #create consolidate

d3={} # create dictionary

for k in l1: #iterate through the loop

for number in k: #iterate through the loop d3[number]=d3. get (number, 0) + 1 #increment the value

return d 3 #return

print (consolidate ([1,2,3], [1,1,1], [2,4], [1])) #display

Explanation:

1

Following are the description of program

Create a dictionary i. e"dict_intersect (d1, d2) " in this dictionary created a dictionary d3. After that iterated the loop and check the condition. If the condition is true then add the items into the dictionary and return the dictionary d3. Finally print them that are specified in the given question.

2

Following are the description of program

Create a dictionary consolidate inside that created a dictionary "d3". After that iterated the loop outer as well as inner loop and increment the value of items. Return the d3 dictionary and print the dictionary as specified in the given question.