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17 January, 16:32

A ball A is thrown vertically upward from the top of a 30-m-high building with an initial velocity of 5 m>s. At the same instant another ball B is thrown upward from the ground with an initial velocity of 20 m>s. Determine the height from the ground and the time at which they pass.

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  1. 17 January, 20:09
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    s = 20.4 m

    Explanation:

    First lets write down equations for each ball:

    s=so+vo*t+1/2a_c*t^2

    for ball A:

    s_a=30+5*t+1/2*9.81*t^2

    for ball B:

    s_b=20*t-1/2*9.81*t^2

    to find time deeded to pass we just put that

    s_a = s_b

    30+5*t-4.91*t^2=20*t-4.9*t^2

    t=2 s

    now we just have to put that time in any of those equations an get distance from the ground:

    s = 30 + 5*2 - 1/2*9.81 * 2^2

    s = 20.4 m
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