A particle has an initial velocity of v0 = 14 ft/s to the right, at s0 = 0, and a = 2 ft/s2 to the left. determine its position t=10 s.

The particle is 40 m to the right of its initial position.

Explanation:

Given data

Initial velocity (v₀) : 14 ft/s (in direction to the positive x-axis) Initial position (s₀) : 0 m Acceleration (a) : - 2 ft/s² (in direction to the negative x-axis)

We can determine the position of the particle at a time t = 10 s, using the following kinematic expression.

s = s₀ + v₀. t + 1/2. a. t²

s (10) = 0 m + 14 ft/s * 10 s + 1/2 * (-2 ft/s²) * (10 s) ²

s = 40 m

The particle is 40 m to the right of its initial position.