Ask Question
17 July, 20:37

If pure oxygen is fed in excess by 25%, what would the fractional conversion of methane be for the final concentration of CO2 in the outlet stream, in mole percent, to be 10%?

+4
Answers (1)
  1. 17 July, 21:59
    0
    Answer:the fractional conversion of methane is 12.5%

    Explanation:The reaction represent the combustion of methane to produce Co2 and steam.

    CH4 + 2O2_CO2 + 2H2O

    From gay lussac law of proportionality

    1mol of CH4 requires 2mol of Oxygen to produce 1 mol of CO2 and 2mol of H2O

    So from the combining ratio, 25% of O2 will fractional produce 25*1/2% of CH4.

    While 12.5% of CO2 and 25% of steam is also produced. so in essence 2.5% of CO2 was lost in the reaction.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If pure oxygen is fed in excess by 25%, what would the fractional conversion of methane be for the final concentration of CO2 in the outlet ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers