A container ship is 240 m long and 22 m wide. Assume that the shape is like a rectangular box. How much mass does the ship carry as load if it is 10 m down in the water and the mass of the ship itself is 30 000 tonnes?

22800 tonne

Explanation:

Given:

Length of the container, L = 240 m

Width of the container, B = 22 m

Depth inside the water, H = 10 m

Mass of the ship, m = 30000 tonnes

Now,

Total immersed volume of the ship = LBH = 240 * 22 * 10 = 52800 m³

From the Archimedes principle, we have

Total mass of the ship (i. e mass of the ship along with the load carried)

= Mass of the volume of water displaced by ship

= 52800 * Density of water

also,

Density of water = 1000 kg/m³

thus,

Total mass of the ship (i. e mass of the ship along with the load carried)

= 52800 * 1000 kg

also,

1 tonne = 1000 kg

thus,

Total mass of the ship (i. e mass of the ship along with the load carried)

= 52800 tonne

Therefore,

the load carried by the ship = Total mass of the ship - mass of ship

or

the load carried by the ship = 52800 - 30000 = 22800 tonne