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13 July, 21:46

The Reynolds number, rhoVD/μ is a very important parameter in fluid mechanics. Determine its value for ethyl alcohol flowing at a velocity of 4 m/s through a 2-in.-diameter pipe.

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  1. 13 July, 23:39
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    The Reynold Number is 146415.34

    Explanation:

    The density of ethyl alcohol = ρ = 789 kg/m^3

    The dynamic viscosity of ethyl alcohol = μ = 0.001095 kg/m. s

    Velocity = V = 4 m/s

    Diameter of pipe = D = 2 in = 0.0508 m

    The Reynold's number (Re), will be:

    Re = ρVD/μ

    Re = (789 kg/m^3) (4 m/s) (0.0508 m) / (0.001095 kg/ms)

    Re = 146415.34
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