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20 January, 12:56

What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C

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  1. 20 January, 16:08
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    331809.5gallon/hr or 92.16gallon/s

    Explanation:

    What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C

    convert 9.4 acre to inches we have=5.896*10^7

    How to calculate Peak runoff discharge

    1. take the dimension of the roof

    2. multiply the dimension by the n umber of inches of rainfall

    3. Divide by 231 to get gallon equivalence (because 1 gallon = 231 cubic inches)

    5.896*10^7*1.3

    7.66*10^7 cubic inches/hr

    1 gallon=231 cubic inches

    7.66*10^7 cubic inches=331809.5gallon/hr or 92.16gallon/s

    this is gotten by converting 1 hr to seconds

    331809.5gallon/hr / 3600s=92.16gallon/s
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