Ask Question
24 June, 10:29

Compute the heat of vaporization at 37 0C. Find the data you need in a good source and cite it properly. Give a qualitative explanation for the difference between the values at 250Cand 37 0C.

+4
Answers (1)
  1. 24 June, 10:44
    0
    at 100g and 37oC

    Hv=154882J/Kg

    at 100g and 25oC

    Hv=104650J/Kg

    Explanation:

    The amount of energy required is called the heat of vaporization. The heat of vaporization is different for all substances, but is a constant for each individual substance.

    Hv = heat of vaporization

    q = heat

    m = mass

    for this question we wil bel taking a sample of 100g of water. But we know the heat q. so,

    To calculate the amount of heat released in a chemical reaction, use the equation Q = mc ΔT, where Q is the heat energy transferred (in joules), m is the mass of the liquid being heated (in kilograms), c is the specific heat capacity of the liquid (joule per kilogram degrees Celsius), and ΔT is the change in.

    Specific heat capacity of water = c = 4,186 J/kg degrees C

    At 37oC

    ΔT = (37-0) = 37

    Q=100x4186x37 = 15,488,200J

    Therefore,

    Hv=15488200/100=154882J/Kg

    At 25oC

    ΔT = (25-0) = 25

    Q=100x4186x25 = 10,465,000J

    Hv=10465000/100=104650J/Kg

    So we can see that at high temperatures a great deal of heat is dispensed.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Compute the heat of vaporization at 37 0C. Find the data you need in a good source and cite it properly. Give a qualitative explanation for ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers