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20 December, 13:17

An axial compressive load of 708 kN is applied to a cylindrical component, 81 mm in diameter and 418 mm long, made of aluminium. Calculate the compressive stress, fc

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  1. 20 December, 14:38
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    The compressive stress of aplying a force of 708 kN in a 81 mm diamter cylindrical component is 0.137 kN/mm^2 or 137465051 Pa ( = 137.5 MPa)

    Explanation:

    The compressive stress in a cylindrical component can be calculated aby dividing the compressive force F to the cross sectional area A:

    fc = F/A

    If the stress is wanted in Pascals (Pa), F and A must be in Newtons and square meters respectively.

    For acylindrical component the cross sectional area A is:

    A=πR^

    If the diameter of the component is 81 mm, the radius is the half:

    R=81mm / 2 = 40.5 mm

    Then A result:

    A = 3.14 * (40.5 mm) ^2 = 5150.4 mm^2

    In square meters:

    A = 3.14 * (0.0405 m) ^2 = 0.005150 m^2

    Replacing 708 kN to the force:

    fc = 708 kN / 5150.4 mm^2 = 0.137 kN/mm^2

    Using the force in Newtons:

    F = 70800 N

    Finally the compressive stress in Pa is:

    fc = 708000 / 0.005150 m^2 = 137465051 Pa = 137 MPa
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