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2 May, 09:29

What is the thermal energy contained within a cubic kilometre of granite (in barrels of oil equivalent) for every one degree change in temperature? Use the following parameters in your calculation: Specific heat of granite = 790 (J/kgC) Density of granite = 2700 kg/m3 Energy in 1 barrel of oil = 6.118e9 J

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  1. 2 May, 09:57
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    348643.34 barrels of oil

    Explanation:

    Given;

    Volume of the granite = 1 km³ = 1000³ m³

    Specific heat of granite, C = 790 J/kg.°C

    Density of granite = 2700 kg/m³

    Energy in 1 barrel of oil = 6.118 * 10⁹ J

    For every 1° change in temperature, ΔT = 1°C

    Now,

    The thermal energy stored is given as;

    Thermal energy = mCΔT

    where, m is the mass

    the mass of 1 km³ of granite = Density * Volume

    or

    the mass of 1 km³ of granite = 2700 * 1000³ = 27 * 10¹¹ Kg

    therefore,

    Thermal energy = 27 * 10¹¹ * 790 * 1

    or

    Thermal energy = 21330 * 10¹¹ J

    hence,

    the thermal energy in terms of barrels of oil

    = Total thermal energy / Energy stored in 1 barrel of oil

    = 21330 * 10¹¹ J / (6.118 * 10⁹ J per barrel)

    = 348643.34 barrels of oil
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