Ask Question
13 March, 20:49

7. D7 A cylindrical brass rod having a minimum tensile strength of 450 MPa (65,000 psi), a ductility of at least 13%EL, and a final diameter of 12.7 mm (0.50 in.) is desired. Some brass stock of diameter 19.0 mm (0.75 in.) that has been cold worked 35% is available. Describe the procedure you would follow to obtain this material. Assume that brass experiences cracking at 65%CW.

+3
Answers (1)
  1. 13 March, 22:53
    0
    Answer: CW = 59%

    Explanation:

    Given dа ta:

    Do = ?

    D1 = 12.7mm

    Average = 28% CW

    %CW = π ([Do/2]^2 - π [ D1/2]^2) / π [ Do/2 ]^2 * 100

    Input data into the formula

    28 = π ([Do/2]^2 - π [ 12.7/2]^2) / π [ Do/2 ]^2 * 100

    Do = 15.1mm

    When CW = 35%

    35 = π ([Do/2]^2 - π [ 35/2]^2) / π [ Do/2 ]^2 * 100

    = 23.6mm

    Now we calculate the total CW needed.

    CW = π ([Do/2]^2 - π [ D1/2]^2) / π [ Do/2 ]^2 * 100

    When Do = 23.6mm

    D1 = 15.1mm

    %CW = π ([23.6/2]^2 - π [ 15.1/2]^2) / π [ 23.6/2 ]^2 * 100

    CW = 59%
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “7. D7 A cylindrical brass rod having a minimum tensile strength of 450 MPa (65,000 psi), a ductility of at least 13%EL, and a final ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers