An electric winch operates on 140 volts [V] and draws 6 amperes [A] of current. The winch has an efficiency of 64 %. The winch is used to lift an object that weighs 510 pound-force [lb Subscript f ] for 11 seconds [s]. Determine the height the object is lifted to, in units of meters [m].

Question

Engineering

Echo

25 January, 18:22

An electric winch operates on 140 volts [V] and draws 6 amperes [A] of current. The winch has an efficiency of 64 %. The winch is used to lift an object that weighs 510 pound-force [lb Subscript f ] for 11 seconds [s]. Determine the height the object is lifted to, in units of meters [m].

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Frederick Clark · Answer 1

efficiency = (energy output / energy input)

energy input = ivt where i is current = 6 A, v is volts = 140 and t time = 11 seconds

energy input = 6 * 140 * 11 = 9240 J

energy output = 0.64 * 9240 = 5913.6 J

510 pound-force = 2268.593 N

at height h, potential energy = mgh = 5913.6 J

2268.593 * h = 5913.6

h = 5913.6 / (2268.593) = 2.61 m