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29 August, 11:12

A multilane highway (two lanes in each direction) is on level terrain. The free-flow speed has been measured at 45 mi/h. The peak-hour directional traffic flow is 1300 vehicles with 8% heavy vehicles. If the peak-hour factor is 0.85, determine the highway's level of service.

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  1. 29 August, 11:21
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    17.71 veh/mi/ln

    Explanation:

    Given,

    Free Flow Speed, FFS = 45 mph

    Number of lanes in each direction = 2

    Peak Flow, V = 1300 veh/hr

    Peak-hour factor = 0.85

    HV = 8 %

    Level Terrain

    fHV = 1 / (1 + 0.08 (1.5-1)) = 1/1.04 = 0.96

    fP = 1.0

    Peak Flow Rate, Vp = V / (PHV*n*fHV*fP) = 1300 / (0.96*2*0.85*1.0) = 796.57 ~ 797 veh/hr/ln

    Vp < 1400

    S = FFS = 45 mph

    Density = Vp/S = (797) / (45) = 17.71 veh/mi/ln

    Density of LOS B should lie between 11 - 18 veh/mi/ln
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