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4 March, 10:40

An n-type semiconductor is known to have an electron concentration of 3 ' 1018 m-3. If the electron drift velocity is 100 m/s in an electric field of 500 V/m. Calculate the mobility and conductivity of this material

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  1. 4 March, 11:03
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    Electron Mobility of the material = 0.20 m2/V-s

    Conductivity of the material = 0.096 (Ω-m) - 1

    Explanation:

    Electron mobility = Vd/E

    = 100/500

    = 0.20 m2/V-s

    Conductivity = σ = n |e|μ

    = 3 x 1018 x 1.602 x 10 - 19 x 0.20

    = 0.096 (Ω-m) - 1
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