Ask Question
7 October, 14:44

During a solar eclipse, the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99 * 10 30 kg, 5.98 * 10 24 kg, and 7.36 * x10 22 kg, respectively. The Moon's mean distance from Earth is 3.84 * 10 8 m, and Earth's mean distance from the Sun is 1.50 * 10 11 m. The gravitational constant is G = 6.67 * 10 - 11 Nm 2 / kg 2.

+1
Answers (1)
  1. 7 October, 18:36
    0
    2.3733 x 10²⁰ N

    Explanation:

    mass of sun Ms = 1.99 x 10³⁰ kg

    Mass of earth Me = 5.98 x 10²⁴ kg

    Mass of moon m ' = 7.36 x 10²² kg

    Mean distance between sun and earth r = 1.5x10¹¹ m

    Mean distance between earth and moon r ' = 3.84 x10⁸ m

    Gravitational constant G = 6.67 x 10⁻¹¹N m² / kg²

    Gravitational force between earth and moon F = GMem' / r '²

    Substitute values you get F = 1.9908 x 10²⁰ N

    This force is towards earth.

    Gravitational force between sun and moon is F ' = GMsm' / (r - r ') ²

    Substitute values you get F ' = 4.3641x10²⁰ N

    This force is towards sun.

    Net force on moon F net = F ' - F

    = 2.3733 x10²⁰ N

    Direction : Towards sun
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “During a solar eclipse, the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational force acting ...” in 📙 Geography if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers